STUDENT SPACE · TOPIC 1

Moles, mass and particles

Convert between mass, amount in moles and number of particles.

The essentials

  • One mole contains 6.02 × 10²³ specified particles for CIE calculations.
  • Name the particles: atoms, molecules, ions or formula units.
  • 12 g carbon and 24 g magnesium each contain 1 mol of atoms.
  • Molar mass M is the mass of one mole, in g/mol.

Key vocabulary

EnglishChinese
mole摩尔
molar mass摩尔质量
Avogadro constant阿伏伽德罗常数

Quick practice

Try each question before opening its hint or answer. Use paper for calculations and diagrams.

Question 1

How many molecules are in 0.10 mol of any molecular substance?

Need a hint for Question 1?

Use the relationships above and check particle ratios and units.

Check Question 1

0.10 × 6.02 × 10²³ = 6.02 × 10²² molecules.

Question 2

Calculate the mass of 0.20 mol CO₂. M(CO₂) = 44 g/mol.

Need a hint for Question 2?

Use mass = moles × molar mass.

Check Question 2

m = nM = 0.20 × 44 = 8.8 g.

Question 3

A 6.0 g sample contains 0.10 mol of molecules. Find its molar mass.

Need a hint for Question 3?

Rearrange amount = mass / molar mass.

Check Question 3

M = m/n = 6.0/0.10 = 60 g/mol.

Use Lesson 1 in your worksheet for written practice. Your teacher will discuss those answers in class.

PREDICT · TRY · EXPLAIN · 3–5 MINUTES

From mass to moles to mass

Predict the product mass. Reveal each step and explain why the equation ratio is not a mass ratio.

2Mg + O₂ → 2MgO

Assume excess oxygen and complete reaction. M(Mg) = 24 g mol⁻¹; M(MgO) = 40 g mol⁻¹.

  1. Step 1 · Convert the known mass into moles.
  2. Step 2 · Use the balanced equation to find product moles.
  3. Step 3 · Convert product moles into mass.

Explain: why must we divide by one molar mass and multiply by another? Display values are rounded; calculations use full precision.

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