STUDENT SPACE · TOPIC 3

Gas volumes at room conditions

Use molar gas volume and gas ratios, including a purity calculation.

The essentials

  • At room temperature and pressure, 1 mol of gas occupies 24 dm³.
  • Use 24 with dm³, or 24 000 with cm³.
  • 0.960 dm³ CO₂ at RTP corresponds to 0.960/24 = 0.0400 mol.
  • Its mass is 0.0400 × 44 = 1.76 g.

Key vocabulary

EnglishChinese
molar gas volume气体摩尔体积
room temperature and pressure室温和常压
volume ratio体积比

Quick practice

Try each question before opening its hint or answer. Use paper for calculations and diagrams.

Question 1

A student calculates 480 ÷ 24 = 20 mol for 480 cm³ gas at RTP. Correct the calculation.

Need a hint for Question 1?

Use the relationships above and check particle ratios and units.

Check Question 1

480/24 000 = 0.0200 mol, or 0.480/24 = 0.0200 mol.

Question 2

CaCO₃ → CaO + CO₂. Find the CO₂ volume at RTP from complete decomposition of 2.50 g pure CaCO₃. M(CaCO₃) = 100 g/mol; molar gas volume = 24 dm³/mol.

Need a hint for Question 2?

Convert carbonate mass to moles, use the ratio, then multiply by 24.

Check Question 2

n = 2.50/100 = 0.0250 mol; V = 0.600 dm³ = 600 cm³.

Question 3

N₂(g) + 3H₂(g) → 2NH₃(g). What volume of H₂ reacts with 20 cm³ N₂ at the same temperature and pressure?

Need a hint for Question 3?

At the same temperature and pressure, gaseous volumes follow the mole ratio.

Check Question 3

H₂ volume = 3 × 20 = 60 cm³.

Use Lesson 3 in your worksheet for written practice. Your teacher will discuss those answers in class.

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