STUDENT SPACE · TOPIC 3
Gas volumes at room conditions
Use molar gas volume and gas ratios, including a purity calculation.
The essentials
- At room temperature and pressure, 1 mol of gas occupies 24 dm³.
- Use 24 with dm³, or 24 000 with cm³.
- 0.960 dm³ CO₂ at RTP corresponds to 0.960/24 = 0.0400 mol.
- Its mass is 0.0400 × 44 = 1.76 g.
Key vocabulary
| English | Chinese |
|---|
| molar gas volume | 气体摩尔体积 |
| room temperature and pressure | 室温和常压 |
| volume ratio | 体积比 |
Quick practice
Try each question before opening its hint or answer. Use paper for calculations and diagrams.
Question 1
A student calculates 480 ÷ 24 = 20 mol for 480 cm³ gas at RTP. Correct the calculation.
Need a hint for Question 1?
Use the relationships above and check particle ratios and units.
Check Question 1
480/24 000 = 0.0200 mol, or 0.480/24 = 0.0200 mol.
Question 2
CaCO₃ → CaO + CO₂. Find the CO₂ volume at RTP from complete decomposition of 2.50 g pure CaCO₃. M(CaCO₃) = 100 g/mol; molar gas volume = 24 dm³/mol.
Need a hint for Question 2?
Convert carbonate mass to moles, use the ratio, then multiply by 24.
Check Question 2
n = 2.50/100 = 0.0250 mol; V = 0.600 dm³ = 600 cm³.
Question 3
N₂(g) + 3H₂(g) → 2NH₃(g). What volume of H₂ reacts with 20 cm³ N₂ at the same temperature and pressure?
Need a hint for Question 3?
At the same temperature and pressure, gaseous volumes follow the mole ratio.
Check Question 3
H₂ volume = 3 × 20 = 60 cm³.
Use Lesson 3 in your worksheet for written practice. Your teacher will discuss those answers in class.
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